1t^2-4t+4=0

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Solution for 1t^2-4t+4=0 equation: 



1t^2-4t+4=0

We add all the numbers together, and all the variables

t^2-4t+4=0

a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{4}{2}=2$

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